# Line slope calculator 5x+3y=60

**Straight line given by points A[6; 10] and B[9; 5]**

## Calculation:

**Slope-intercept form of line:**y = -1.6667x+20

**Canonical form of the line equation:**5x+3y-60 = 0

**Parametric form of the line equation:**

x = 3t+6

y = -5t+10 ; t ∈ R

**Slope:**m = -1.6667

**Slope angle of line: φ =**-59°2'10″ = -1.0304 rad

**X intercept:**x

_{0}= 12

**Y intercept:**y

_{0}= q = 20

**Distance line from the origin:**d

_{0}= 10.2899

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(3; -5)

**Normal vector: n =**(5; 3)

**Midpoint of the segment AB: M =**[7.5; 7.5]

**Perpendicular Bisector equation:**3x-5y+15 = 0

**Vector OA = (6; 10) ; |OA| = 11.6619**

**Vector OB = (9; 5) ; |OB| = 10.2956**

**Scalar product OA .OB = 104**

**Angle ∠ AOB = 29°58'54″ = 0.5233 rad**